You have three resistors of values 2Ω, 3Ω and 5Ω

You have three resistors of values 2Ω, 3Ω and 5Ω. How will you join them so that the total resistance is more than 7Ω?

  1. Draw a diagram for the arrangement.
  2. Calculate the equivalent resistance.

Answer

  1.  RR = 2 + 3 + 5 = 10 Ω                                                                                                                                                                                         (Only 10 Ω can be accepted if the diagram is shown else substitution is a must.)