A half metre rod is pivoted at the centre with two weights of 20 gf and 12 gf suspended at a perpendicular distance of 6 cm and 10 cm from the pivot respectively as shown below.

- Which of the two forces acting on the rigid rod causes clockwise moment?
- Is the rod in equilibrium?
- The direction of 20 kgf force is reversed. What is the magnitude of the resultant moment of the forces on the rod?

- 12 kg f
- Yes
- On reversing the direction of 20 kg f, the magnitude of the resultant forces on the rod = 20 × 6 + 12 × 10 = 240